Mr.Chan spends $4,000,000 on a flat at the beginning of 2008.The value $V of the flat after N years can be represented by the following formula:
$V=k X 1.03^n , where k is a constant.
(a) Find the value of k
V = 4,000,000x1.03^n
k=4,000,000
(b)What will be the increase in the value of the flat from the time of purchase to beinning of 2015? (Give the answer correct to nearest $10,000)

我識計啦(b)原來係要correct to nearest $10,000
The time of purchase to beinning of 2015 is
V=4,000,000x1.03^(2015-2008)
V=49194954.62
V=9194954 (correct to nearest $10,000)

V=9200000(correct to nearest $10,000)